diff --git a/Recursive-Grid-Tiling/README.md b/Recursive-Grid-Tiling/README.md new file mode 100644 index 0000000..079fa5d --- /dev/null +++ b/Recursive-Grid-Tiling/README.md @@ -0,0 +1,157 @@ +# Coding 2: Recursive Grid Tiling + +## Grid Tiling + +Here's an interesting theorem: consider a square grid of squares with sides +given by some power of (i.e. a grid of size $2^n \times 2^n$) like this example +of a $2^3 \times 2^3$ grid: + + + +If you select exactly one grid square to remove (which is colored black below), +then the remaining squares can be tiled by 3-square L-shape tiles, like this. + + + +The proof of this fact is inductive and leads to a simple recursive algorithm +for producing a tiling. Assume that you can tile any $2^{n-1} \times 2^{n-1}$ +grid with a single square removed with L-shaped tiles. Suppose we are given a +$2^n \times 2^n$ grid with one square removed. + +Here's an example of what we've got: + + + +How can we use our inductive hypothesis to show that the entire grid can be +tiled? Well, let's start by splitting our grid vertically and horizontally in +half: + + + +Notice that this splits our $2^n \times 2^n$ sized grid into four +$2^{n-1} \times 2^{n-1}$ sized sub-grids, and one of them (the top left in our +example above) already has a square removed _but notice that three of them do +not yet have a square removed_. This means we can use our inductive hypothesis +to tile whichever sub-grid contains the square we already wanted removed: + + + +But now we're a bit stuck, because the conditions of the inductive hypothesis +apply if we have a $2^{n-1} \times 2^{n-1}$ grid with one square removed, but +instead we have three $2^{n-1} \times 2^{n-1}$ grids with no squares removed. +But now notice the following trick. We can place a single L-tile that covers +exactly one grid square in each of three sub-grids that we haven't yet tiled! + + + +But notice that since this new L-tile covers exactly one square from each of the +three untiled sub-grids, we now have three $2^{n-1} \times 2^{n-1}$ each with a +single square removed and so the inductive hypothesis now applies! We can tile +each quadrant individually using the inductive hypothesis. + + + +Then + + + +Then + + + +And finally, with the red dividing lines removed: + + + +The base case for this induction are the 2x2 grids, which become L-tiles if we +remove anyone grid square. + +## Your Task + +You are going to write a program to compute L-tilings of $2^n \times 2^n$ square +grids. You will assign each tile a number starting with 00. The first tile you +generate should have all of its grid cells marked with a 00, the next tile 01, +etc. + +### Input + +The first line of input will give the grid size parameter n as an integer. The +second line will contain the index (i, j) of the removed tile. + +### Output + +Your code should output $2^n$ lines, each containing $2^n$ 2-digit numbers +separated by spaces (and formatted so that single digit numbers have a leading +0). The value of each grid location should be the tile index you generated. (You +may assume you won't need 3 digits). + +
| Sample Input | +Sample Output | +
3 |
+
+ +-1 02 03 03 07 07 08 08 +02 02 01 03 07 06 06 08 +04 01 01 05 09 09 06 10 +04 04 05 05 00 09 10 10 +12 12 13 00 00 17 18 18 +12 11 13 13 17 17 16 18 +14 11 11 15 19 16 16 20 +14 14 15 15 19 19 20 20+ |
+
3 |
+
+ +02 02 03 03 07 07 08 08 +02 01 -1 03 07 06 06 08 +04 01 01 05 09 09 06 10 +04 04 05 05 00 09 10 10 +12 12 13 00 00 17 18 18 +12 11 13 13 17 17 16 18 +14 11 11 15 19 16 16 20 +14 14 15 15 19 19 20 20+ |
+
4 |
+
+ +03 03 04 04 08 08 09 09 24 24 25 25 29 29 30 30 +03 02 02 04 08 07 07 09 24 23 23 25 29 28 28 30 +05 02 06 06 10 10 07 11 26 23 27 27 31 31 28 32 +05 05 06 01 01 10 11 11 26 26 27 22 22 31 32 32 +13 13 14 01 18 18 19 19 34 34 35 35 22 39 40 40 +13 12 14 14 18 17 17 19 34 33 33 35 39 39 38 40 +15 12 12 16 20 17 21 21 36 36 33 37 41 38 38 42 +15 15 16 16 20 20 21 00 00 36 37 37 41 41 42 42 +45 45 46 46 50 50 51 00 66 66 67 67 71 71 72 72 +45 44 44 46 50 49 51 51 66 65 65 67 71 70 70 72 +47 44 48 48 52 49 49 53 68 65 -1 69 73 73 70 74 +47 47 48 43 52 52 53 53 68 68 69 69 64 73 74 74 +55 55 56 43 43 60 61 61 76 76 77 64 64 81 82 82 +55 54 56 56 60 60 59 61 76 75 77 77 81 81 80 82 +57 54 54 58 62 59 59 63 78 75 75 79 83 80 80 84 +57 57 58 58 62 62 63 63 78 78 79 79 83 83 84 84+ |
+